Problem

Compare the domain and range of each function: Function A is given by \(P(t)=3t+5\) for integer values of \(t\) from \(1~\text{to}~4\), and Function B is given by \(P(x)=3x+5\) for real values of \(x\) from \(1~\text{to}~4\).

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Both functions have domain 1,2,3,4 and range 8,11,14,17 because substituting 1, 2, 3, and 4 gives the outputs 8, 11, 14, and 17.

For P(t)=3t+5, the domain is [1,4] and the range is 8,11,14,17; for P(x)=3x+5, the domain is 1,2,3,4 and the range is [8,17].

Both functions have domain [1,4] and range [8,17] because they both use the rule P=3(input)+5 and both go from input 1 to input 4.

For P(t)=3t+5, the domain is 1,2,3,4 and the range is 8,11,14,17 because t is restricted to integers; for P(x)=3x+5, the domain is [1,4] and the range is [8,17] because x can be any real number from 1 to 4.

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Compare the domain and range of each function: Function A is given by \(P(t)=3t+5\) for integer values of \(t\) from \(1~\text{to}~4\), and Function B is given by \(P(x)=3x+5\) for real values of \(x\) from \(1~\text{to}~4\).

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