Problem

Store A has median price $\$25$ and $IQR$ $\$8$; store B has median price $\$31$ and $IQR$ $\$8$. Calculate the center and spread differences and state the contextual conclusion.

Source statistical display: Prices: store A median$25,IQR$8; store B median$31,IQR$8. No requested comparison or classification is annotated.

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median difference=$31−$25=$6, so A more expensive because its median is lower; IQR difference=$8−$8=$0, so middle-half spreads are equal; conclusion=A higher typical price with equal spread

median difference=$31-$25=$6, so B is typically more expensive; IQR difference=$8-$8=$0, so middle-half spreads are equal; conclusion=B has higher typical prices with the same IQR spread

median difference=$31−$25=$6, so typical prices are the same because IQRs match; IQR difference=$8−$8=$0, so middle-half spreads are equal; conclusion=same typical prices and spread

median difference=$31−$25=$6, so B typically costs more; IQR difference=$8−$8=$0, so B more spread because its median is higher; conclusion=B higher and more variable

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Store A has median price \(\$25\) and \(IQR\) \(\$8\); store B has median price \(\$31\) and \(IQR\) \(\$8\). Calculate the center and spread differences and state the contextual conclusion.

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