Problem preview

A-SSE.1.b Warmup M2-009-A05-V04

Interpret quadratic/exponential expressions by treating sub-expressions as meaningful units.

Use a difference table to bracket a solution of f(x) = g(x)

Problem

Interpret and evaluate \(Q=300(0.9)^2\). Describe the retained factor and percent decay for each of two intervals, calculate the compounded multiplier, and apply it to the initial value.

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Initial 300; factor 0.9; −10% each interval; 2 intervals; multiplier 1 − 0.9 − 0.9 = −0.8; Q = −240.

Initial 300; factor 0.9; −20% total by multiplying −10% by 2; 2 intervals; multiplier 0.8; Q = 240.

Initial 300; factor 0.9; −10% each interval; 2 intervals; multiplier 0.9² = 0.81; Q = 243.

Initial 300; factor 0.9; −10% each interval; 2 intervals; multiplier (300 · 0.9)²; Q = 72,900.

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Curriculum context

Course: Math II
Standard: A-SSE.1.b
Category: Algebra
Domain: Seeing Structure in Expressions
Objective: Interpret quadratic/exponential expressions by treating sub-expressions as meaningful units.
Problem type: Use a difference table to bracket a solution of f(x) = g(x)