Problem

Use the displayed graphs to analyze \(P(t)=100(1.2)^t+50\) with an existing base group. Separate the additive \(50\) from the growing component, evaluate \(P(0)\), and explain why \(50\) is not a future limiting population.

Unannotated graph of P(t)=100(1.2)^t+50 people; the curve begins at 150 and grows, but baseline and component labels are withheld.

Answer choices

Choose your path.

Preview only

Baseline 50 people per interval; component 100(1.2)t people; P(0) = 150 people; 50 people are added every interval; the model is linear.

Baseline 150 people; component 100(1.2)t people; P(0) = 150 people; the component grows without bound; 150 is the future limiting population.

Baseline 50 people; component 100(1.2)t people; P(0) = 150 people; the component decays toward 0; the long-run population is 50 people.

Baseline 50 people; component 100(1.2)t people; P(0) = 150 people; the component grows without bound; 50 is an additive base group, not a future limiting population.

The choices are visible. Checking your work and seeing which answer is correct happen inside Gozunta.

Use the displayed graphs to analyze \(P(t)=100(1.2)^t+50\) with an existing base group. Separate the additive \(50\) from the growing component, evaluate \(P(0)\), and explain why \(50\) is not a future limiting population.

Turn the preview into practice.

Gozunta lets you study this problem—and more than 10,000 others.