Problem

Interpret \(t-2\) within \(h(t)=-16(t-2)^{2}+64\) when \(t\) is seconds after launch. Identify the reference time, units, sign before and after that time, and why the signed offset—not its absolute value—is the quantity being squared.

Answer choices

Choose your path.

Preview only

Subexpression t − 2; signed time relative to peak; units feet; negative before 2 feet and positive after; it is the time-offset factor.

Subexpression t − 2; whole height; units feet; negative before 2 seconds and positive after; it is the model output.

Subexpression t − 2; absolute elapsed time from the peak; units seconds; it is never negative; it is the time-offset factor being squared.

Subexpression t − 2; signed time relative to the 2-second peak; units seconds; negative before 2 seconds and positive after; it is the time-offset factor being squared.

The choices are visible. Checking your work and seeing which answer is correct happen inside Gozunta.

Interpret \(t-2\) within \(h(t)=-16(t-2)^{2}+64\) when \(t\) is seconds after launch. Identify the reference time, units, sign before and after that time, and why the signed offset—not its absolute value—is the quantity being squared.

Turn the preview into practice.

Gozunta lets you study this problem—and more than 10,000 others.