Write the monic factored polynomial whose zeros are \(3\) and \(-5\). Expand it, compare the \(x\)-term with \(x^{2}+bx-15\), find \(b\), and verify the constant term from the factors.

Answer choices

Choose your path.

Preview only

Using only root 3 gives b = −3. Both zeros are needed to determine the polynomial.

The root sum is −2, so b = −2. The coefficient relation is −b = −2, which gives b = 2.

The root product is −15, so b = −15. The product determines the constant term, not the x-coefficient.

The root sum is −2, so −b = −2 and b = 2. The factors (x − 3)(x + 5) expand to x² + 2x − 15.

The choices are visible. Checking your work and seeing which answer is correct happen inside Gozunta.

Inside Gozunta

More than a preview

Create targeted learning sessions, use hints, check your answer, read the walkthrough, watch the video, print the work, and track your progress.

Discover Gozunta Try it now

Curriculum context