Problem

Complete the square for \(h(t)=-16t^{2}+64t+5\), showing the scaled constant correction. Use the vertex to give the admissible maximizing time in seconds and interpret the maximum height in feet.

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h(t) = −16(t − 2)² + 69, so the maximum height is 69 feet. The maximizing time and its domain status are not given.

h(t) = −16(t − 2)² + 69, so t = 2 seconds gives 69 feet. The time is not checked against t ≥ 0.

h(t) = −16(t − 2)² + 69, so t = 2 feet and the maximum is 69 seconds. The input and output units are reversed.

h(t) = −16(t − 2)² + 69. The maximum occurs at admissible time t = 2 seconds and is 69 feet, so the model predicts a maximum height of 69 feet after 2 seconds.

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Complete the square for \(h(t)=-16t^{2}+64t+5\), showing the scaled constant correction. Use the vertex to give the admissible maximizing time in seconds and interpret the maximum height in feet.

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