Factor a monic quadratic to reveal zeros

Problem

Factor monic quadratic x²−7x+12 and reveal its zeros. Enter product/sum targets, integer pair, factored form, all zeros, and coefficient/root check.

Your answer

A target product=12; target sum=-7; integer pair=correct; factored=(x−3)(x−4); zeros=x=3 only; check=one factor set to zero B target product=12; target sum=-7; integer pair=-3,-4; factored=(x−3)(x−4); zeros=x=3,4; check=sum roots7 gives coefficient-7 and product12 C target product=12; target sum=-7; integer pair=correct; factored=(x−3)(x−4); zeros=-3,-4; check=factor constants copied without solving D target product=12; target sum=-7; integer pair=3,4; factored=(x+3)(x+4); zeros=-3,-4; check=product target matches but middle-term sum has opposite sign

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Factor a monic quadratic to reveal zeros

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Hint

Solution walkthrough

Find the factor pair

Write the factored form

Set each factor equal to zero

State the factorization and zeros

Another way

Common mistake