All courses Algebra I · A-SSE.1.a 13 of 76
Interpret terms, factors, and coefficients in linear and exponential expressions.

Interpret a coefficient as a rate or per-unit change

Problem
In \(C~=~8t~+~20\), \(C\) is cost in dollars and \(t\) is the number of tickets. Interpret the coefficient as an output change and contextual rate.
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Hint

Look at the number multiplying t in 8t.

In a linear expression, the coefficient tells how much the output changes for each increase of 1 in the variable.

Solution walkthrough

01

Separate the variable term from the constant

\[C~=~8t~+~20~->~\text{variable}~\text{term}~=~8t;~\text{constant}~\text{term}~=~20\]

Only 8t changes when the ticket count t changes. The 20-dollar term is fixed and is not the requested coefficient.

02

Identify the coefficient and units

\[8t~=~(8~\text{dollars}/\text{ticket})(t~\text{tickets})\]

The coefficient multiplying t is 8. Because C is measured in dollars and t in tickets, its contextual unit is dollars per ticket.

03

Verify the per-unit change

\[C(t~+~1)~-~C(t)~=~[8(t~+~1)~+~20]~-~[8t~+~20]~=~8\]

Increasing the input by one ticket increases the output by 8 dollars, while the fixed 20 cancels from the change.

04

State the coefficient interpretation

\[\text{The}~\text{coefficient}~\text{is}~8:~\text{for}~\text{each}~1~\text{ticket},~C~\text{increases}~by~\$8,~\text{so}~\text{the}~\text{rate}~\text{is}~\$8~\text{per}~\text{ticket}.\]

This reports the coefficient, signed output change, input unit, and contextual rate requested.

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Another way

  1. Compare C(1) = 28 and C(2) = 36. The one-ticket increase changes cost by 36 - 28 = 8 dollars.

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Common mistake

Do not call 20 the per-ticket rate. It is the constant starting fee; the number attached to t controls the change for each additional ticket.

Solution walkthrough video