Problem preview
MF.EQ.6 Standard MF-033-A06-V01

Solve two-step equations and justify each inverse operation.

Solve a fixed two-step context model

Problem

A gym charges \(\$6~\text{once}\) plus \(\$4\) per class for a \(\$30\) total. Complete the fixed model and solve: \(6~+~4x~=~30\); \(x~=~\text{\_\_\_}\) classes.

Big Picture

What this problem is really about

The six-dollar charge is fixed, while four dollars repeats for every class, so those quantities play different roles in the model. Reverse the cost-building process by removing the one-time charge before dividing by the per-class rate. The final unit should be classes, and rebuilding the total checks the interpretation.

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Four variants of this problem type
Curriculum context
Standard
MF.EQ.6
Category
Pre-Algebra
Domain
Equations
Objective
Solve two-step equations and justify each inverse operation.
Problem type
Solve a fixed two-step context model