Problem preview
MF.EQ.6 Standard MF-033-A07-V01

Solve two-step equations and justify each inverse operation.

Match a context to the right two-step equation

Problem

A bike rental costs \(\$8~\text{once}\) plus \(\$5~\text{per}~\text{hour}\) for a \(\$33\) total. Verify the candidate equation structures, then solve the valid equation. Report its letter followed by the rental time.

A. \(5h~+~8~=~33\)
B. \(5(h~+~8)~=~33\)
C. \(33h~+~8~=~5\)

Big Picture

What this problem is really about

Match each story quantity to its role before solving: five dollars repeats per hour, eight dollars is charged once, and thirty-three dollars is the total. A valid model keeps the fixed fee outside the hourly multiplication. Remove that fee first, then divide by the rate to recover time in hours.

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Four variants of this problem type
Curriculum context
Standard
MF.EQ.6
Category
Pre-Algebra
Domain
Equations
Objective
Solve two-step equations and justify each inverse operation.
Problem type
Match a context to the right two-step equation