Problem

Container A is an open \(10~\text{in}\). by \(6~\text{in}\). by \(4~\text{in}\). box. Container B consists of \(\text{one}\) \(10\text{-}by-6\) base, \(\text{two}\) \(10\text{-}by-4\) sides, and \(\text{two}\) \(6\text{-}by-4\) sides. Calculate and compare their surface areas.

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Container A: (10×6)+(10×4)+(6×4)=124 in²; Container B: (10×6)+(10×4)+(6×4)=124 in²; the surface areas are equal.

Container A: (10×6)+2(10×4)+2(6×4)=188 in²; Container B: (10×6)+2(10×4)+2(6×4)=188 in²; the surface areas are equal.

Container A: 2(10×6)+2(10×4)+2(6×4)=248 in²; Container B: 2(10×6)+2(10×4)+2(6×4)=248 in²; the surface areas are equal.

Container A: (10×6)+2(10×4)+2(6×4)=188 in²; Container B: 2(10×6)+2(10×4)+2(6×4)=248 in²; the surface areas are not equal.

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