The target theoretical probability of blue is \(1/4\). Evaluate candidates A–E, then report the \(\text{complete}~\text{matching}~\text{set}\).
A. A spinner has \(8~\text{equal}~\text{sections}\): \(2\) blue, \(3\) red, \(3\) yellow.
B. A bag has \(3\) blue, \(5\) green, and \(4\) white marbles; \(\text{one}~\text{marble}\) is drawn at random.
C. A box has \(6\) blue and \(18\) non-blue tiles; \(\text{one}~\text{tile}\) is drawn at random.
D. A spinner has \(12\) equal sections: \(3\) blue, \(4\) red, \(5\) green.
E. A deck has \(5\) blue cards and \(15\) cards of other colors; \(\text{one}~\text{card}\) is drawn at random.
What this problem is really about
Test every scenario with the same ratio: blue outcomes divided by all equally likely outcomes. Build each total by including every color or by adding blue and non-blue counts, then reduce the fraction and compare it with the target. This catches equivalent fractions while preventing a non-blue subtotal from being mistaken for the denominator.