Problem

An amount grows by \(10\%~\text{each}~\text{equal}~\text{interval}\). Interpret \(\log~\text{base}~1.1~\text{of}~2\) by stating the factor and rate, target multiple, logarithmic interval count, decimal approximation, and exponential equation.

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Candidate analysis: The factor is 1.1 (10% growth), the target is twice the initial amount, and the interval count is ln(2)/ln(1.1) ≈ 0.14 because 1.1count = 2.

Candidate analysis: The factor is 1.1 (10% growth), the target is twice the initial amount, and the interval count is ln(2)/ln(1.1) ≈ 7.27 because 1.1count = 2.

Candidate analysis: The factor is 2 (10% growth), the target is 1.1 times the initial amount, and the interval count is ln(2)/ln(1.1) ≈ 7.27 because 1.1count = 2.

Candidate analysis: The factor is 1.1 (110% growth), the target is twice the initial amount, and the interval count is ln(2)/ln(1.1) ≈ 7.27 because 1.1count = 2.

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An amount grows by \(10\%~\text{each}~\text{equal}~\text{interval}\). Interpret \(\log~\text{base}~1.1~\text{of}~2\) by stating the factor and rate, target multiple, logarithmic interval count, decimal approximation, and exponential equation.

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