Problem

An amount has \(\text{one}~\text{half}\text{-}\text{life}~\text{per}~\text{equal}~\text{interval}\). Interpret \(\log~\text{base}~0.5~\text{of}~0.125~=~3\) by stating the decay factor and rate, target fraction and percent, interval count, and exponential check.

Answer choices

Choose your path.

Preview only

Candidate analysis: The factor is 0.5 (50% decay), the target is 1/8 or 12.5% of the initial amount, and it takes 3 intervals because 0.5³ = 0.125.

Candidate analysis: The factor is 0.125 (50% decay), the target is one half or 50% of the initial amount, and it takes 3 intervals because 0.5³ = 0.125.

Candidate analysis: The factor is 0.5 (50% growth), the target is 1/8 or 12.5% of the initial amount, and it takes 3 intervals because 0.5³ = 0.125.

Candidate analysis: The factor is 0.5 (50% decay), the target is 1/8 or 12.5% of the initial amount, and it takes 8 intervals because 0.5³ = 0.125.

The choices are visible. Checking your work and seeing which answer is correct happen inside Gozunta.

An amount has \(\text{one}~\text{half}\text{-}\text{life}~\text{per}~\text{equal}~\text{interval}\). Interpret \(\log~\text{base}~0.5~\text{of}~0.125~=~3\) by stating the decay factor and rate, target fraction and percent, interval count, and exponential check.

Turn the preview into practice.

Gozunta lets you study this problem—and more than 10,000 others.