Evaluate every candidate below against the ratio \(4~\text{red}~\text{tiles}\) to \(6~\text{blue}~\text{tiles}\).
1. Ratio \(2:3\)
2. Ratio \(6:4\)
3. Table: \(\text{red}~4\), \(\text{blue}~6\); \(\text{red}~8\), \(\text{blue}~12\); \(\text{red}~12\), \(\text{blue}~18\)
4. Table: \(\text{red}~4\), \(\text{blue}~6\); \(\text{red}~6\), \(\text{blue}~9\); \(\text{red}~8\), \(\text{blue}~11\)
5. Diagram description: each group shows \(2~\text{red}~\text{counters}\) and \(3~\text{blue}~\text{counters}\)
6. Statement: “For every \(3~\text{red}~\text{tiles}\), there are \(2~\text{blue}~\text{tiles}\).”
Include every candidate equivalent to \(4:6\).
What this problem is really about
We need every representation that preserves both the red-to-blue order and the value of four to six. We’ll simplify the reference ratio, test each standalone ratio and statement against that benchmark, and inspect every row of each table rather than accepting a partial match. A diagram qualifies only if each repeated group keeps the same relationship.