California course

Math I

Build connected understanding across quantities, equations, functions, coordinate geometry, congruence, and data.

Problem types
659
Practice variants
2,636
Problem types

Page 2 of 19

Each problem type has four distinct practice variants. Open a preview to move among all four.

A-CED.4 M1-004-A01-V01

Rearrange a formula by dividing to isolate the target

Rearrange formulas to isolate a chosen quantity and interpret the result.

The target variable is attached to another quantity by multiplication. We’ll treat the other symbols as known, undo that multiplication by dividing both sides by the complete factor, and simplify …

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A-CED.4 M1-004-A02-V01

Rearrange a formula by undoing an outer factor and then isolating the variable inside a group

Rearrange formulas to isolate a chosen quantity and interpret the result.

The parentheses reveal the operation layers around the target variable. We’ll work from the outside inward: first undo the factor multiplying the entire group, then undo the addition still inside …

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A-CED.4 M1-004-A03-V01

Rearrange a quotient formula to solve for the denominator variable and state restrictions

Rearrange formulas to isolate a chosen quantity and interpret the result.

The target begins in a denominator, so we’ll clear that fraction before trying to isolate it. Multiplying by the original denominator turns the relationship into a product; then dividing by …

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A-CED.4 M1-004-A04-V01

Use a square root and choose the meaningful branch

Rearrange formulas to isolate a chosen quantity and interpret the result.

Undoing a square produces two algebraic branches, so the algebra and the context both matter. We’ll take square roots to expose the positive and negative possibilities, then use the meaning …

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A-CED.4 M1-004-A05-V01

Rearrange a linear formula to isolate a chosen variable, especially when that variable appears in more than one term

Rearrange formulas to isolate a chosen quantity and interpret the result.

The target variable appears in two separate terms, so trying to divide immediately would leave part of it behind. We’ll first combine those terms by factoring out the shared target, …

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A-CED.4 M1-004-A06-V01

Rearrange a formula with inverse operations when the target variable appears in one term

Rearrange formulas to isolate a chosen quantity and interpret the result.

We’ll read the operation layers around the requested length and undo them in reverse order. First remove the term that does not contain the target; then divide the complete remaining …

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A-CED.4 M1-004-A08-V01

Rearrange a formula to isolate a chosen variable, then substitute values to find its value

Rearrange formulas to isolate a chosen quantity and interpret the result.

This task has a symbolic stage and a numerical stage, and keeping them in that order makes the variable roles clear. We’ll isolate time by undoing its multiplication by the …

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A-CED.4 M1-004-A09-V01

Rearrange a formula by clearing a fraction or denominator to isolate a variable

Rearrange formulas to isolate a chosen quantity and interpret the result.

The fraction here is a coefficient multiplying the target, not a denominator containing the target. We’ll first remove the added constant, then multiply the entire remaining side by the reciprocal …

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A-CED.4 M1-004-A10-V01

Rearrange a linear formula with subtraction or a negative coefficient to solve for a chosen variable

Rearrange formulas to isolate a chosen quantity and interpret the result.

The negative coefficient makes sign tracking the central issue. We’ll move the constant away from the target term, divide by the full signed coefficient, and then rewrite the negative quotient …

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A-CED.4 M1-004-A11-V01

Rearrange a formula and state the variable restrictions that make the new equation valid

Rearrange formulas to isolate a chosen quantity and interpret the result.

The original equation and the rearranged equation can impose restrictions at different moments. We’ll record the variable forbidden by the starting denominator before clearing it, then note the variable used …

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A-CED.4 M1-004-A12-V01

Decide whether two algebraic forms are equivalent rearrangements of a formula

Rearrange formulas to isolate a chosen quantity and interpret the result.

Equivalence should be tested by transforming one form into the other, not by judging how different they look. We’ll start with the grouped quotient, apply its common divisor to every …

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A-REI.1 M1-005-A01-V01

Name the equality property used in a solving step

Explain equation-solving steps as logical consequences of equality and justify solution methods.

An equality property is named for the operation performed between lines, not merely for a symbol visible in the starting equation. We’ll compare the before-and-after forms, reconstruct the same hidden …

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A-REI.1 M1-005-A02-V01

Justify an algebraic transformation

Explain equation-solving steps as logical consequences of equality and justify solution methods.

Only the left expression changes while the right side stays fixed, so this is an equivalent rewrite rather than an operation on both sides. We’ll track the outside factor to …

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A-REI.1 M1-005-A03-V01

Find the first invalid solving step

Explain equation-solving steps as logical consequences of equality and justify solution methods.

An error audit must move in chronological order, because later work may be consistent with an already broken equation. We’ll compare each line with the one immediately before it, beginning …

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A-REI.1 M1-005-A06-V01

Verify a solution by substitution

Explain equation-solving steps as logical consequences of equality and justify solution methods.

Verification means testing the proposed value in the original equation, not simply trusting the solving work that produced it. We’ll replace the variable while preserving the equation’s operation order, evaluate …

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A-REI.1 M1-005-A07-V01

Classify an equation as one solution, no solution, or infinitely many solutions

Explain equation-solving steps as logical consequences of equality and justify solution methods.

The solution count is determined by what remains after both sides are simplified, not by the equation’s original appearance. We’ll expand the grouped side, combine like terms, and compare the …

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A-REI.1 M1-005-A09-V01

Decide whether a transformation creates an equivalent equation

Explain equation-solving steps as logical consequences of equality and justify solution methods.

Two equations are equivalent only when their complete solution sets match. We’ll identify the balanced operation connecting these forms, check that applying it forward preserves equality, and then reverse it …

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A-REI.1 M1-005-A10-V01

Clear denominators in an equation

Explain equation-solving steps as logical consequences of equality and justify solution methods.

Clearing a denominator is a whole-equation operation. We’ll use a common-denominator multiplier on every term on both sides, so the fractional term cancels while equality is preserved. After simplifying the …

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A-REI.1 M1-005-R04-V01

Test whether one equation step is equivalent

Explain equation-solving steps as logical consequences of equality and justify solution methods.

This audit concerns a local rewrite on one side, so the unchanged right side is not evidence of an imbalance. We’ll multiply the existing outside factor by every term in …

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A-REI.1 M1-005-R08-V01

Complete an equality-preserving solution chain

Explain equation-solving steps as logical consequences of equality and justify solution methods.

A correct endpoint is not enough; every arrow in the solution chain must preserve equality. We’ll first rewrite the grouped expression and combine its constants, then use the same inverse …

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A-REI.10 M1-006-A01-V01

Test whether an ordered pair satisfies an equation

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

An ordered pair supplies values for both variables, with the input first and the output second. We’ll substitute each coordinate into its matching position, evaluate the expression that predicts the …

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A-REI.10 M1-006-A02-V01

Generate ordered-pair solutions from input values

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

The equation acts as one input-output rule for all three supplied inputs. We’ll substitute each input separately, use parentheses around the negative value to protect its sign, and keep the …

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A-REI.10 M1-006-A04-V01

Identify listed points that are not solutions

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

Every listed point needs its own test; one successful point says nothing about the others. For each pair, we’ll use the x-coordinate to compute the output required by the equation …

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A-REI.10 M1-006-A05-V01

Choose the table that matches an equation

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

A table represents the equation only if every row is an ordered-pair solution. We’ll read each row from the supplied tables, calculate the output predicted by the rule for its …

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A-REI.10 M1-006-A06-V01

Match graph features to a linear equation

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

Slope-intercept form gives each graph feature a different symbolic role. We’ll place the line’s rise-over-run in the coefficient position and its vertical-axis crossing in the constant position, keeping their signs …

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A-REI.10 M1-006-A07-V01

Interpret an ordered-pair solution with units

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

The ordered pair has to be interpreted in the equation’s variable order, not by the sizes of its numbers. We’ll identify which variable is the input and which is the …

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A-REI.10 M1-006-A08-V01

Represent a vertical or horizontal solution set

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

An equation naming only one coordinate fixes that coordinate and leaves the missing one free. We’ll describe every solution as an ordered pair with the stated first coordinate and an …

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A-REI.10 M1-006-A09-V01

Find an equation that fits plotted solution points

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

The plotted points reveal both pieces of a linear rule. We’ll calculate the constant change in output per unit change in input to get the slope, then use the point …

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A-REI.10 M1-006-A10-V01

Test every row in a table and locate violations

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

The word “every” makes this a row-by-row test, so early successes cannot settle the question. We’ll use each x-entry to compute the output required by the equation and compare it …

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A-REI.10 M1-006-A12-V01

Verify consistency across equation, table, and graph features

Understand that a two-variable equation's graph is the set of all ordered-pair solutions.

Consistency requires agreement across all three representations, not just a few matching numbers. We’ll generate the equation’s outputs at the table inputs and compare them row by row, then decode …

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A-REI.11 M1-007-A01-V01

Find an exact intersection by solving f(x) = g(x)

Solve equations of the form f(x)=g(x) approximately by finding graph/table intersections.

At an intersection, the two rules produce the same output from the same input. We’ll set their output expressions equal and solve that equation for the shared input, then substitute …

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A-REI.11 M1-007-A02-V01

Estimate an intersection point from a graph description

Solve equations of the form f(x)=g(x) approximately by finding graph/table intersections.

The graph gives an estimate, so the goal is to enclose the crossing rather than claim more precision than the scale supports. We’ll read the horizontal and vertical coordinates separately, …

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A-REI.11 M1-007-A03-V01

Use a table to locate where two functions are equal

Solve equations of the form f(x)=g(x) approximately by finding graph/table intersections.

We’ll compare the two output columns at each common input, first looking for a row where the values are exactly equal. If no row matches, adjacent inputs where the functions …

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A-REI.11 M1-007-A04-V01

Interpret an intersection point in context

Solve equations of the form f(x)=g(x) approximately by finding graph/table intersections.

The coordinates must be translated through the axes before the intersection can be interpreted. We’ll attach the input unit to the first coordinate and the output unit to the second, …

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A-REI.11 M1-007-A05-V01

Find intersection points of a line and a quadratic

Solve equations of the form f(x)=g(x) approximately by finding graph/table intersections.

A line and a quadratic can meet more than once, so we have to account for every shared input. We’ll set their output expressions equal, move everything into a zero-product …

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A-REI.11 M1-007-A06-V01

Approximate a crossing point from a function-comparison table

Solve equations of the form f(x)=g(x) approximately by finding graph/table intersections.

A table can show an intersection exactly, so we should look for equality before settling for an interval estimate. We’ll compare both output entries in every common-input row. If a …

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